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leetcode 946 验证栈序列


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给定 pushed 和 popped 两个序列,每个序列中的 值都不重复,只有当它们可能是在最初空栈上进行的推入 push 和弹出 pop 操作序列的结果时,返回 true;否则,返回 false 。

示例 1:

输入:pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
输出:true
解释:我们可以按以下顺序执行:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

示例 2:

输入:pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
输出:false
解释:1 不能在 2 之前弹出。

提示:

0 <= pushed.length == popped.length <= 1000
0 <= pushed[i], popped[i] < 1000
pushed 是 popped 的排列。
class Solution:
    def validateStackSequences(self, pushed: List[int], popped: List[int]) -> bool:
        stack = []
        while len(pushed) > 0:
            stack.append(pushed[0])
            pushed = pushed[1:]
            while len(stack) > 0 and len(popped) > 0 and stack[-1] == popped[0]:
                stack.pop()
                popped = popped[1:]
        return len(stack) == 0